Electric Field Strength: Calculating for 0.75 g Plastic Bead

AI Thread Summary
To determine the electric field strength needed to suspend a 0.75 g plastic bead charged with 8.28×10^10 excess electrons, the weight of the bead must equal the electric force acting on it. The weight can be calculated using the formula W = mg, where m is the mass and g is the acceleration due to gravity. The electric force is given by F = E*q, where E is the electric field strength and q is the charge of the bead. By equating the weight to the electric force, the electric field strength can be calculated as E = W/q. This approach simplifies the problem to balancing gravitational and electric forces.
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Electric field...please help!

Homework Statement


A 0.75 g plastic bead is charged by the addition of 8.28×10^10 excess electrons. What electric field (strength) will cause the bead to hang suspended in the air?


Homework Equations





The Attempt at a Solution


Doesn't E have to equal the weight? So would I just calculate the weight of the bead? That seems to easy though...
 
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The weight and the charge. Also, remember Force = E*q.
 
So...
(K*Q1*Q2) / R^2 = (KQ1) / R^2 * Q
And then I solve for Q?
But then I get Q2 = Q?? I am confused...
 
Let E be the unknown electric field. Then what is the force it exerts on a charge q? I've already told you...
 
E = Force / Q
Force = K*Q1*Q2 / r^2
 

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