Electric field strength of van de graff generator

AI Thread Summary
The discussion revolves around calculating the electric field strength produced by a Van de Graaff generator (VDGG) with a dome radius of 0.15m and a potential difference (PD) of 75kV. The stored charge on the generator is noted as 5.0 x 10^-6C. Participants are using the formula E = kQ/r² for their calculations, but there is confusion regarding the correct application of the radius and whether it should be squared. One participant arrives at an electric field strength of 2.0 x 10^6, while another cites a provided answer of 3.0 x 10^5, leading to discussions about potential errors in the provided equation. Clarification is sought on the correct approach to the calculations.
thisischris
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A VDGG is used to produce a large PD. The dome of the generator has a radios of 0.15m. It is charged and gets a PD between the dome and the Earth of 75kV.

The charged stored on it is : 5.0 x 10-6C

Answer: Use of E = Q/4∏εr0. 3.0 x 105

My attempt: E = kQ/r2 = 8.99 x 109 x 5.0 x 10-6 / 0.152 = 2.00 x 106

I get the provided answer if I don't square the 0.15. It also seems to be a potential print error as r is not squared in their equation as well as having a 0 as a sub-ponent(opposite of exponent?)... Could anyone share any light on this?

Much appreciated :)
 
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Uh what is the question?
 
Sorry, long day!

I get an answer of 2.0 x106, while the provided answer is 3.0 x 105.
 
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