Electric field, surface charge density

AI Thread Summary
The discussion centers on understanding the expression for the potential difference Vab in relation to electric fields and surface charge density. The user is confused about deriving this expression using the relationship ΔV = -∫E dl. It is suggested that expressing the electric field E in terms of the electric displacement D can clarify the derivation. Additionally, applying Gauss' law for D to relate it to the free charge Q on the inner conductor is recommended. This approach aims to provide a clearer understanding of the relationship between electric fields, potential difference, and charge distribution.
Cocoleia
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Homework Statement


upload_2017-2-26_12-51-39.png


Homework Equations

The Attempt at a Solution


I have the full solution, the first part being:
upload_2017-2-26_12-52-38.png

I don't understand how they came up with the expression for Vab. I know usually ΔV=-∫E dl, but I'm not sure how they found their expression. Can someone explain? Thanks.
 
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Cocoleia said:
I know usually ΔV=-∫E dl, but I'm not sure how they found their expression.
Yes, you can think of their expression as coming from ΔV=-∫E dl if you express E in terms of D. Use Gauss' law for D to obtain an explicit expression for D in terms of the free charge Q on the inner conductor.
 
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