Electric Fields: Charge/Unit Length on Inner Surface of Coaxial Cable

AI Thread Summary
In the discussion about the charge per unit length on the inner surface of a coaxial cable, participants explore the application of Gauss's law. The theory suggests that when a hollow cylindrical metal tube surrounds a wire with infinite charge, the inner surface of the tube will not have zero charge. Instead, due to the conductive properties of the metal, charges will redistribute themselves, creating a charge density on the inner surface. The radial distance of 2.5mm is relevant for calculating the electric field using the formula E = λ/(2πε_0 r). Overall, the scenario emphasizes the importance of understanding charge distribution in conductive materials within electric fields.
steph124355
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I'm a little stuck on the theory behind this question:

(in relation to a line of infinite charge: a wire)
A hollow cylindrical metal tube with inner radius 2.5mm is now placed around the wire, to form a coaxil cable. What will be the charge per unit length on the inner surface of the tube. Explain.

I am thinking it is 0, how or why i got that I don't know!
 
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Hint: Make use of Gauss's law.
 
Use Gauss' law as though the cylinder is not there?
In which case to calculate using E= λ/(2πε_0 r) and use the 2.5mm as the radial distance?

Is there any different concepts behind this scenario compared to using a gaussian surface?
 
steph124355 said:
(in relation to a line of infinite charge: a wire)

Infinite charge...wow...wonder how that happens
 
Its not 0. Considering that metals are good conductors, what happens is that when placed in an electric field, a polar accumulation of charges occur (meaning the positive charges go in one direction and the negative in the other). Therefore, charges accumulate on the surfaces of the cylinder. The inner surface will have a charge density.
 
haha thanks!
physics does my head in but i enjoy it!
thanks for your help
 

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