Electric flux through a circular plate

AI Thread Summary
The discussion centers on calculating electric flux through a circular plate by relating it to the flux through a spherical surface. The approach involves using a sphere centered at charge Q and deriving the flux through a spherical surface created by a circle defined by radius r=5. The participants debate the correct formula for electric flux, questioning why it is expressed as Q/4πεr² instead of Q/ε. There is also a suggestion to use the area of the spherical cap to find the flux, with a focus on the relationship between the angles and dimensions involved. Overall, the conversation highlights the complexities of applying electric field concepts to specific geometrical configurations.
rolls
Messages
50
Reaction score
0
http://img508.imageshack.us/img508/7047/problemhi1.jpg

Now I have gone about solving this problem by drawing a sphere with Q centred in it, let's call this sphere A1, now this circle defined by r=5 (lets call this circle C) cuts this sphere perfectly creating a spherical surface let's call As.

Now we know the electric flux through As will be the same as the area defined by the circle C so we can find the electric flux by finding the total electric flux through A and * it by the ratio of As/A.

So now we have: (sorry I don't know latex)
Ea1 = flux through A1 (sphere)
Eas = flux through As (spherical surface)

Eas = Ea1 * As/A1

A1 = 4*Pi*r^2
As = 2*Pi*r(r-d)
r = Sqrt(a^2 + d^2)
r = 5.83
Ea1 = Q/4*Pi*E0*r^2

Eas = Q/4*Pi*E0*r^2 * 2*Pi*r(r-d) / 4*Pi*r^2

Now I haven't bothered to simply it and calculate an answer but does this look correct?
 
Last edited by a moderator:
Physics news on Phys.org
Yeah it looks ok. Funny that they would actually give you the formula for surface area of a spherical cap and even tell you explicitly how to substitute the variables.
 
Well it was the first question in the course, I've only have 1 lecture on the material so I really did need that hint.
 
can anybody explain why flux is taken as (q/4phiepselon r^2) [which is the formula for field]and not as q/epsilon?please reply soon
 
sanjanaraj said:
can anybody explain why flux is taken as (q/4phiepselon r^2) [which is the formula for field]and not as q/epsilon?please reply soon
Probably not!

As implied by your question, it looks like the given solution was in error - in just the way you suspect.
 
i would probably go about this question in the below mentioned way:-

consider a imaginary sphere S centered at Q,the circle cuts the sphere creating a spherical surface A.The flux through the circle is same as the flux through the spherical surface.
let the radii of the sphere subtend an angle 2(alpha) at the centre such that
tan(alpha) = a/d
now area of spherical surface,As=2*phi*a(1-cos(alpha) )
flux through the spherical surface = (q/epsilon)*2*phi*a(1-cos(alpha)) / {4*phi*(a^2 + d^2)
thus flux through the circular surface =
{q*a[1-(d/root(a^2+d^2)]}/{2*epsilon*(a^2+d^2)}is it correct?
 
I think AS should be given by:A_S=2\pi Rh=2\pi R(R-d)=2\pi R^2(1-d/R)=2\pi R^2(1-\cos(\alpha))=2\pi (a^2+d^2)(1-\cos(\alpha))\,.
 
Back
Top