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**1. The problem is:**

A vertical wall (5.9m x2.5m) in a house faces due east. A uniform electric field has a magnitude of 150 N/C. This field is parallel to the ground and points 35degrees north of east. What is the electric flux through the wall?

A vertical wall (5.9m x2.5m) in a house faces due east. A uniform electric field has a magnitude of 150 N/C. This field is parallel to the ground and points 35degrees north of east. What is the electric flux through the wall?

**2. Homework Equations :**

Electric flux is found by using E cos of angle between electric field and normal.

E= f/q

Electric flux is found by using E cos of angle between electric field and normal.

E= f/q

**3. The Attempt at a Solution**

Well, I tried it this way and don't think it is right.

E= 150 N/C

_______

(5.9 x 2.5m) x cos 35 degrees

I think the answer will be radially outward as oposed to inward, but I am not too sure.

The answer choices we were given are

A. 7.9 x 10*5 radially outward

B. 3.2 x 10*5 radially outward

C.1.4 x 10*6 ......inward

D. 5.9 x 10*5....inward

E. zero

I don't see how it would be zero, and I think I have narrowed it down to either A or B.Well, I tried it this way and don't think it is right.

E= 150 N/C

_______

(5.9 x 2.5m) x cos 35 degrees

I think the answer will be radially outward as oposed to inward, but I am not too sure.

The answer choices we were given are

A. 7.9 x 10*5 radially outward

B. 3.2 x 10*5 radially outward

C.1.4 x 10*6 ......inward

D. 5.9 x 10*5....inward

E. zero

I don't see how it would be zero, and I think I have narrowed it down to either A or B.

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