1. The problem is: A vertical wall (5.9m x2.5m) in a house faces due east. A uniform electric field has a magnitude of 150 N/C. This field is parallel to the ground and points 35degrees north of east. What is the electric flux through the wall? 2. Relevant equations: Electric flux is found by using E cos of angle between electric field and normal. E= f/q 3. The attempt at a solution Well, I tried it this way and don't think it is right. E= 150 N/C _______ (5.9 x 2.5m) x cos 35 degrees I think the answer will be radially outward as oposed to inward, but I am not too sure. The answer choices we were given are A. 7.9 x 10*5 radially outward B. 3.2 x 10*5 radially outward C.1.4 x 10*6 ......inward D. 5.9 x 10*5....inward E. zero I don't see how it would be zero, and I think I have narrowed it down to either A or B.