Electric Flux Through Spherical Surface Centered at Origin

AI Thread Summary
A uniform linear charge density of 4.0 nC/m is distributed along the x-axis, and the problem involves calculating the electric flux through a spherical surface with a radius of 5.0 cm centered at the origin. The correct approach involves using the formula for charge Q=λL, where L should be 2R instead of 2πR, as the charge is only along the axis. The initial calculations led to an incorrect flux value, but the realization that L equals 2R clarified the misunderstanding. The correct electric flux through the surface is determined to be 45 N m²/C. Understanding the geometry of the charge distribution is crucial for accurate calculations.
rizamadiyar
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A uniform linear charge density of 4.0 nC/m is distributed along the entire x axis. Consider a spherical (radius = 5.0 cm) surface centered on the origin. Determine the electric flux through this surface.

Homework Equations


L=2rπ
φ=Q/ε
λ=Q/L

The Attempt at a Solution


I found the charge by substituting values into Q=λL, then I found the flux, but the answer I get is incorrect, the correct one is 45 N m2/C

What am I missing?
 
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rizamadiyar said:
I found the charge by substituting values into Q=λL,
Where L is what? You wrote L=2πr. Is that what you used? On what basis?
 
haruspex said:
Where L is what? You wrote L=2πr. Is that what you used? On what basis?
Oh, I got this, L=2R, not 2πR, since the charge is distributed on the axis. Am I right?
 
rizamadiyar said:
Oh, I got this, L=2R, not 2πR, since the charge is distributed on the axis. Am I right?
Yes.
 

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