Electric flux through the earth

AI Thread Summary
The discussion revolves around calculating the electric flux through the Earth and determining the Earth's charge based on a downward-pointing electric field of 140 N/C. The user initially attempted to solve the problem using the formula for electric flux but received an incorrect answer. It was pointed out that the sign of the flux matters, as the question specifically asks for the flux "out of the Earth." The user acknowledged the misunderstanding and expressed gratitude for the clarification. Understanding the directionality of electric flux is crucial for solving such problems correctly.
sashab
Messages
12
Reaction score
0

Homework Statement



The Earth's radius is 6370 km . There is a downward-pointing electric field in the atmosphere above the Earth's surface, of average magnitude 140. N/C .

a) What is the flux of the electric field out of the Earth?
b) What is the charge on the Earth?


Homework Equations



\Phi=\vec{E}\bulletA

The Attempt at a Solution



I figured that this would be a simple problem of the electric flux through a sphere, so I thought if I used the above equation and by plugging in the area of the sphere I would get the right answer for a), but the computer is saying I'm incorrect. :( I got an answer of 7.13x10^16 N*m^2/C. I know that flux involves integration, but I'm only just starting to learn it so I don't know how to use integration in a problem like this yet. Any help would be really appreciated! Thanks
 
Physics news on Phys.org
sashab said:

Homework Statement



The Earth's radius is 6370 km . There is a downward-pointing electric field in the atmosphere above the Earth's surface, of average magnitude 140. N/C .

a) What is the flux of the electric field out of the Earth?
b) What is the charge on the Earth?


Homework Equations



\Phi=\vec{E}\bulletA

The Attempt at a Solution



I figured that this would be a simple problem of the electric flux through a sphere, so I thought if I used the above equation and by plugging in the area of the sphere I would get the right answer for a), but the computer is saying I'm incorrect. :( I got an answer of 7.13x10^16 N*m^2/C. I know that flux involves integration, but I'm only just starting to learn it so I don't know how to use integration in a problem like this yet. Any help would be really appreciated! Thanks

That's a good try. Though you should say how you got it. The thing you might be missing is that flux can be either negative or positive. The question is asking for the flux "out of the Earth".
 
Dick said:
That's a good try. Though you should say how you got it. The thing you might be missing is that flux can be either negative or positive. The question is asking for the flux "out of the Earth".
Ohh okay I see where I went wrong. Thanks for the help!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top