Electric Field Strength Calculation for a Point Charge

AI Thread Summary
To calculate the electric field strength at a point 3.0 cm from a point charge of +1.0 microcoulomb, the formula E = k * Q / r^2 is used, where k is Coulomb's constant. The discussion clarifies that the displacement vector r represents the distance from the charge to the point where the electric field is being calculated. The electric field strength is derived to be approximately 1.0 x 10^7 N/C. Understanding the relationship between the point charge and the displacement vector is essential for solving the problem. This discussion emphasizes the importance of correctly applying Coulomb's law in electric field calculations.
Ezhil
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Hi
I was just doing my homework and i am stuck on this question. Can you please help me with this?

a) Caluculate the electric field strength E, at a point located 3.0 cm due east from a point charge q=+1.0 microcoulomb.

I know i have to use the formulas:
E = F/q

And Coulomb's law. But to use Coulomb's law you need to two charges and this question only has one. Please help on this, Thankyou.

Ezhil
 
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If the force on q due to Q is
\vec F = qQ \frac {\vec r}{r^3}
then the electric field due to Q is
\vec E = Q \frac {\vec r}{r^3}
 
Am i right in saying:
E = (k*Qsource) / (r^2)

therefore
E=[(9*10^9)*(1.0*10^-6)] / (0.03)^2
E= 1.0*10^7
 
\vec E = Q \frac {\vec r}{r^3}

What is the vector r equal to and is the Q the point charge 1.0 microcoulomb that is given in the problem?
I'm sorry i don't understand the equation completely, I am still in year 11.
 
\vec r is the displacement vector from charge Q to charge q.
 
Thank you for your help!
 
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