Electric potential across a simple circuit

AI Thread Summary
The discussion centers on understanding electric potential in a simple circuit involving a battery, switch, and resistor. When the switch is open, the electric potential remains constant at zero across all components due to the lack of current flow. Upon closing the switch, the potential before the resistor equals the initial potential V_o, while the potential after the resistor drops to zero, resulting in a potential difference of -V_o across the resistor. After a long time with the switch closed, the electric potential remains unchanged, confirming the earlier observations. The importance of defining a reference point for measuring potential differences is emphasized for clarity in analysis.
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Homework Statement


Consider the image and assume that the switch has been open for a long time. Note that the switch is supposed to be between the battery and the resistor on the top straight segment, which is not shown in the image.

http://www.sciencebuddies.org/science-fair-projects/project_ideas/Elec_img160.jpg

Also consider the initial electric potential to be V_o

a) What is the electric potential before and after the battery, switch and resistor?
b) What is the potential across the resistor
c) What is the electric potential at all points (i.e before and after the battery, switch and resistor) immediately after the switch is closed?
d) What is the electric potential difference across the resistor immediately after the switch is closed
e) After a long time after the switch has been closed, what is the electric potential at all points and what is the electric potential difference across the resistor?

Homework Equations



Kirchhoff's loop law:

ΔV_loop = 0

The Attempt at a Solution



I am having some trouble understanding the concept and I am looking for a second opinion towards my responses toward these question.

a) Since the current is broken, there is no change in electric potential (no voltage drop) therefore, before and after the battery, switch and resistor should all be 0

b) Likewise, the electric potential difference across the resistor should be zero

c) Immediately after the switch is closed, from the battery to the point before the resistor, the electric potential should be equal to V_o. After the resistor to the point back to the battery, the electric potential should be 0

d) The electric potential difference will be -V_o

e) After a long time, there should be no change, therefore the answers should be similar to c and d.

Thanks for the help.
 
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chris_0101 said:

Homework Statement


Consider the image and assume that the switch has been open for a long time. Note that the switch is supposed to be between the battery and the resistor on the top straight segment, which is not shown in the image.

http://www.sciencebuddies.org/science-fair-projects/project_ideas/Elec_img160.jpg

Also consider the initial electric potential to be V_o

a) What is the electric potential before and after the battery, switch and resistor?
...snip...

The Attempt at a Solution



I am having some trouble understanding the concept and I am looking for a second opinion towards my responses toward these question.

a) Since the current is broken, there is no change in electric potential (no voltage drop) therefore, before and after the battery, switch and resistor should all be 0
Potential with respect to what? You need to define a reference point with respect to which potential is to be measured (define two points and then determine the potential difference from one to the other). What's your point of reference for the above? Perhaps it's the bottom (negative terminal) of the battery?
 
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