Electric Potential and Consv of Energy, Is this right?

AI Thread Summary
A proton with an initial speed of 800,000 m/s is brought to rest by an electric field, leading to a calculation of the potential difference required to stop it. The kinetic energy was initially miscalculated, but after correcting the velocity squared, the potential difference was found to be approximately -3340V. The discussion highlights the confusion around energy conservation, particularly regarding the role of external forces acting on the proton in the electric field. It is clarified that while electric fields are conservative, energy conservation applies only when internal conservative forces act on the system, excluding external influences. The conversation draws parallels with gravitational fields, emphasizing that external forces can complicate the conservation of energy in different contexts.
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Homework Statement


A proton with an intial speed of 800,000m/s is brought to rest by an electric field.
What was the potential difference that stopped the proton.

Homework Equations


Ki + qvi = Kf + qvf

k=.5mv^2

The Attempt at a Solution



Voltage final = ?
vi = 800,000m/s
v2=0
q=1.60x10^-19
m=1.67x10^-27

ki=.5mv^2
=.5(1.67x10^-27)(800,000)
=6.68x10^-22j

Ki + qVi = Kf + qVf
Ki=-qVi
6.68x10^-22j=(-1.60x10^-19)Vi
-4.175x10^-3=Vi

^^^ is that answer correct?
Its seems weird cause Energy isn't really conserved :s

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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You forgot to square the velocity when you were working out the Kinetic Energy.
 
thank you very much, :)
answer makes more sense now V=-3340V
 
but why will the energy is conserved?
Isn't external force acting on proton?

whats your system?
 
cupid.callin said:
but why will the energy is conserved?
Isn't external force acting on proton?

whats your system?

The "system" is the proton in the electric field. Electric fields are conservative.
 
they are conservative ,,, but energy is only conserved only when internal conservative forces act on the system,

here (acc. to your system) external forces are also acting.
So: Δ(mechanical energy) = work done by external forces
 
cupid.callin said:
they are conservative ,,, but energy is only conserved only when internal conservative forces act on the system,

here (acc. to your system) external forces are also acting.
So: Δ(mechanical energy) = work done by external forces

What external forces would those be?
 
gneill said:
The "system" is the proton in the electric field. Electric fields are conservative.

in the electric field ...
So you mean that whatever is causing electric field is not a part of system, right?

then wouldn't electric force be an external force? ...? :confused:
 
cupid.callin said:
in the electric field ...
So you mean that whatever is causing electric field is not a part of system, right?

then wouldn't electric force be an external force? ...? :confused:

Is the Earth part of the system that contains its gravitational field? Must we abandon conservation of energy when a projectile mass arcs through the Earth's field?
 
  • #10
but in that case we include Earth in our system, don't we?
 
  • #11
cupid.callin said:
but in that case we include Earth in our system, don't we?

More like we ignore it for practical reasons since we consider its mass to be so great that it is unperturbed. It is included when necessary (celestial mechanics, for example), but taken as a whole, when everything is included, the gravitational field is still conservative with regards to potential.

Regarding this question, the electric field is presented as a constant background, just as we take the Earth's gravitational field to be a constant background for our 'lab' experiments.
 
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