Electric Potential and Wave Nature of Matter

AI Thread Summary
An electric potential difference accelerates electrons, which have a wavelength of 1.0 x 10^-11 m, towards a screen. The calculations show that the velocity of the electrons just before impact is approximately 7.28 x 10^7 m/s. Using the kinetic energy equation, the electric potential difference is calculated to be around 15078.52 V. While the physics is confirmed to be correct, there are suggestions to adjust significant figures for clarity. The focus remains on ensuring accurate results for the electric potential difference rather than the velocity.
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Homework Statement


An electric potential difference accelerates electrons from rest position towards a screen.
Just before striking the screen, the electrons have a wavelength of 1.0*10^-11 m
Find the electric potential difference.

Homework Equations



p=h/λ
ΔEK=qΔV

The Attempt at a Solution



p=h/λ
mv=h/λ
v=h/λm
v=(6.63*10^-34)/((1.0*10^-11)(9.11*10^-31))
v=72777167.95 m/s

ΔEK=qΔV
EK2-EK1=eΔV
0.5(9.11*10^-31)(72777167.95)^2 - 0.5(9.11*10^-31)(0)^2 = eΔV
ΔV=0.5(9.11*10^-31)(72777167.95)^2 / e
ΔV=15078.51948 V

Is this correct? (other than significant digits)
 
Last edited:
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Once again your v=(6.63*10^-34) / ( (1.0*10^-11) * (9.11*10^-31) )equation needs some parens

and your v result needs to be significant figure adjusted to be 7.28 x 10^7 m/s

similarly for the delta v result.

Again the physics looks right but someone at PF needs to second it for me.
 
fixed.

the question wasn't asking for velocity so i didn't round it in order to get a more accurate result for electric potential difference
 
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