Electric Potential (Conceptual question)

AI Thread Summary
To derive the equation E = Δv/d in electrostatics, it is essential to understand that ΔEp = -ΔEk indicates a relationship between potential energy and kinetic energy. The negative sign reflects the conservation of energy, where an increase in potential energy results in a decrease in kinetic energy. When deriving E = Δv/d, the negative sign is accounted for by recognizing that the change in potential (Δv) is defined as a decrease in energy per unit charge. Therefore, the equation illustrates how electric field strength (E) relates to the change in electric potential over distance. Understanding these relationships is crucial for solving electrostatics problems effectively.
Fizickstudent
Messages
2
Reaction score
0

Homework Statement


To find "E" in an electrostatics problem when you are given the velocities and/or distance, you would use the formula E = Δv/d.

Given the information below to start out with, derive the equation E = Δv/d and explain what happens to the negative signs (where do they go and why) as you continue to derive the equation.

Given information:
ΔEp = -ΔEk
Δv/d = Eki - Ekf
Δv/d = -1/2mvf^2



Homework Equations


E = Δv/d

The Attempt at a Solution


For me to derive this equation any further to the equation E = Δv/d I will have to somehow get rid of that negative, I was just wondering, what happens to that negative?
 
Physics news on Phys.org
In the given problem delta v is not the change in velocity, but change in potential . Please go through the definition of electric potential at any point due to a charge.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top