Electric potential for an infinite plane charge distribution

[p3rry]

Hello everybody,
I have to calculate the electric field and the potential for a charge q placed at distance d from an infinite plane charge distribution \sigma.

For the electric field there's no problem, but how I can get the electric potential for an infinite charge distribution?

 

[Vanadium 50]

Integrate the field.

 

[p3rry]

ok, but I get an unknown constant.

The field is E=\frac{\sigma}{2\epsilon_{0}} in the x direction. So if I integrate it I get

V(x)=V(0)-\frac{\sigma}{2\epsilon_{0}}x

Where the constant is unknown...maybe I don't need to know it

Further, if I calculate the potential starting from a circular plane distribution and then pulling the radius to infinity I get an infinite potential

 

[gabbagabbahey]

ok, but I get an unknown constant.

The field is E=\frac{\sigma}{2\epsilon_{0}} in the x direction.

No, that's just the field of a uniformly charged plate with surface charge density \sigma... what about the field of the point charge?

So if I integrate it I get

V(x)=V(0)-\frac{\sigma}{2\epsilon_{0}}x

Where the constant is unknown...maybe I don't need to know it

There is always an "unknown constant" when calculating the potential. This is because it is determined from the differential equation \textbf{E}=-\mathbf{\nabla}V, and as you should know, first order DE's need at least one boundary/initial condition to find a unique solution...You are free to choose any value for your constant, simply by choosing a suitable reference point (a point where you define the potential to be zero)...in this case, choosing the origin as a reference point makes things simple (so that V(0)=0).

Further, if I calculate the potential starting from a circular plane distribution and then pulling the radius to infinity I get an infinite potential

Unless you show your calculation, I cannot be certain of your error, but I suspect you are unknowingly choosing your reference point to be at r=infinity...r=infinity is usually a bad choice of reference point when dealing with charge distributions the extend to infinity.