Electric Potential Produced by Point Charge

AI Thread Summary
The discussion revolves around calculating the electric potential produced by a point charge of -8 µC at various coordinates. For points (3.0m, 0) and (-3.0m, 0), the potential is correctly calculated as -23973.3 V using the formula V=kq/r. The confusion arises in calculating the potential at (3.0m, -3.0m), where the distance r is mistakenly considered as 6 instead of the correct value derived from the Pythagorean theorem. Clarification on the coordinate system helps the participant realize the correct distance for the calculation. Understanding the coordinate system is crucial for accurate potential calculations.
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Homework Statement



A point charge of -8 µC is at the origin. What is the electric potential at
(a) (3.0m, 0),
(b) (-3.0m, 0), and
(c) (3.0m, -3.0m)?




Homework Equations



V=kq/r


The Attempt at a Solution



a & b) V=(8.99x10^9)(-8x10^-6)/3
V= -23973.3

c) V=(8.99x10^9(-8x10^-6)/6



I understand part a and b and got the correct answer. However, for part c, the only thing I am doing different is r=6 instead of 3 because the coordinates are (3.0m, -3.0m) and I am not getting the correct answer. I don't really understand. Thank you.
 
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r does not equal 6. Think about the coordinate system.
 
I thought r=6 because there is 3 in the + x direction and 3 in the -x direction on either side of the origin (x=0) so I added them to get a total of 6 from -x to +x. I'm not really sure how to look at the coordinate system any other way?
 
The two numbers denote the x and y coordinates in a cartesian plane. How can you have a position with two x coordinates? Draw the x an y axes and work out what r should be for the (3, -3) point.
 
ohhhh wow I'm so blind. Thank you very much for your help!
 
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