How Fast Does an Electron Move Towards a Charged Plane?

AI Thread Summary
An electron released from rest 4 meters from a positively charged plane experiences a constant electric field of 100 V/m. The force on the electron can be calculated using the equation F = E * Q, resulting in a force of 1.6 x 10^-13 J. The acceleration of the electron is determined using F = ma, yielding an acceleration of approximately 1.756 x 10^13 m/s². To find the final velocity upon collision with the plane, the kinematic equation V_f² = V_i² + 2ad is suggested, where displacement is 4 meters. This approach allows for the calculation of the electron's speed at the moment of impact.
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Homework Statement



An electron is released from rest 4m from an infinite plane of positive charge. The plane produces an electric field with a constant magnitude of 100 V/m. How fast is the electron moving when it collides with the plane? Mass of E = 9.11x10^-31kg.

Homework Equations



Not sure... Ui + Ki = Uf + Kf?

The Attempt at a Solution

 
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You are given the electric field, not the voltage at the point so you can't use conservation of energy. Remember, electric field * charge = force on charge. You can use this to find the force on the electron, and then use one of the kinematics equations so solve for the speed.
 
kkrizka said:
You are given the electric field, not the voltage at the point so you can't use conservation of energy. Remember, electric field * charge = force on charge. You can use this to find the force on the electron, and then use one of the kinematics equations so solve for the speed.

Ok so I did F=EfxQ...(100 v/m)(1.6x10-19) = 1.6x10^-13 J. And then F=ma so A = (1.6x10^-17)/(9.11x10-31) = 1.756x10^13 m/s...

I'm lost what to do after that...what kinematic equation should i use?
 
The one that involves initial, final velocities, acceleration and displacement. I believe it is
V_f^2 = V_i^2 + 2ad
 
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