Electric Potential/Work Question

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When pushing electrons into an electric field with a potential of 1 volt, both 1 and 2 electrons experience the same electric potential of 1 volt. The work done to move the electrons is calculated using the equation W = qV, where q represents the charge. For 2 electrons, the total work required would be 2 electronvolts (eV), as each electron contributes to the total work. The discussion clarifies that the electric potential remains constant regardless of the number of electrons moved along the same path. Understanding these concepts is crucial for solving related physics problems.
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Homework Statement



Work is required to push a solitary electron into an electric field where it attains an electric potential of 1 volt.

a.) If you instead push 2 electrons through the same path, what would the electric potential of the two electrons be? b.) What would the work required to move the electrons be?


Homework Equations



I'm not sure, but I think W = qV may be an equation.


The Attempt at a Solution



I am guessing that is it's 2 volts for a.) and 2 electronvolts for b.), but I could be wrong. Any help would be greatly appreciated... this is very confusing to me. =( Thanks!
 
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Welcome to PF.

If you are pushing something in the field, then 1e or 2e, they will experience then the same ΔV if the statement of the problem is that they are being taken over the same path. 1v then would be the potential at the point that 1 or 2 electrons would be brought.

As you noted though the ΔV*q is the work, so yes you would have imparted 2 ev to the charges (taken together).
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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