Electricity Sparks: Finding the Voltage Difference for a 0.2 cm Jump

AI Thread Summary
To find the minimum voltage difference for a 0.2 cm spark jump, the breakdown electric field (E) for air is crucial, typically around a few million volts per meter. The initial calculation used an incorrect value for E, leading to errors in determining voltage (V). The correct formula is V = Ed, where d should be converted to meters for accuracy. After correcting the electric field value to 3,000,000 V/m, the voltage difference can be accurately calculated. Understanding the breakdown voltage in air is essential for these calculations.
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Suppose that after walking across a carpeted floor you reach for a doorknob, and just before you touch it a spark jumps 0.2 cm between your finger and the doorknob. Find the minimum voltage difference betwen your finger and the doorknob for this to occur.

I did V=Ed

which I plugged in (8.85 x 10^-12)(.2 x 10^-3) and I got this wrong. What am I doing wrong?
 
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whoknows12345 said:
Suppose that after walking across a carpeted floor you reach for a doorknob, and just before you touch it a spark jumps 0.2 cm between your finger and the doorknob. Find the minimum voltage difference betwen your finger and the doorknob for this to occur.

I did V=Ed

which I plugged in (8.85 x 10^-12)(.2 x 10^-3) and I got this wrong. What am I doing wrong?
How are you determining what E is? It seems to be several orders of magnitude out. I think the breakdown E for air is in the order of a few million volts/metre. Also you appear to be using .2 mm not .2 cm.

AM
 
so it would be ((8.85 x 10^-12)/1.00059) x (2.2 x 10^-2) which is 1.769e-14?
 
nevermind, i got it. i was using the wrong E, E was 3,000,000
 
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