Electromagnetics = Biot-Savart Law around square path

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SUMMARY

The discussion focuses on calculating the magnetic field (B-field) at the center of a square loop positioned above the xy-plane, with a current I flowing counter-clockwise. The relevant equation provided is B = [(μo*I*aФ)/(4∏*ρ)](cosα2 – cosα1), leading to the final result B = [(4μo*I)/(∏*w*(√2))]az. Participants express confusion regarding the correct angles α1 and α2 to use in the calculation, specifically needing clarification on their definitions and the setup of the problem.

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satchmo05
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Homework Statement


Find the B-field at the center of the square loop located above the xy plane, with width (w), and current I rotating counter-clockwise.


Homework Equations


Here is the given equation:
B = [(μo*I*aФ)/(4∏*ρ)](cosα2 – cosα1)

The final answer is for the B-field about the loop is:
B = [(4μo*I)/(∏*w*(√2))]az
How do I obtain this answer? I am having trouble with the angles that I am supposed to use.

The Attempt at a Solution


I used (w/2) for the radial component, ρ. I used 45 degrees for α2, and 90 degrees for cosα1, and this is obviously wrong. Which angles do I use to get the correct angle?
 
Last edited:
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Solving this analytically for cosα2 - cosa1, I should receive 2/sqrt(2). How should I set up my angles to achieve this? Thank you for all help, I greatly appreciate it!
 
What kind of picture goes with the given equation? In other words, for what situation was it derived? How are ρ, α1 and α2 defined?
 

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