Calculating the Angle of an Electron Passing Between Charged Plates

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An electron is accelerated by a potential difference of 10,000 V, resulting in a speed of approximately 5.92 x 10^7 m/s before passing between charged plates. The electric field strength between the plates is determined using E = U/d, where U is the potential difference of 200 V and d is the distance of 1.0 cm. The electric force acting on the electron is calculated as F = QE, leading to the determination of the vertical acceleration. By analyzing the motion components, the angle θ at which the electron exits the plates can be calculated. A step-by-step approach involving mechanics and movement principles is essential for finding the resultant velocity and angle.
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Homework Statement



An electron is accelerated horizontally from rest in a television picture tube by a potential difference of 10,000 V. It then passes between two horizontal plates 5.0 cm long and 1.0 cm apart which have a potential difference of 200 V. At what angle θ will the electron be traveling after it passes between the plates?

Homework Equations



-ΔEE = ΔEK
qΔV = 1/2mv^2


The Attempt at a Solution



-ΔEE = ΔEK
qΔV = 1/2mv^2
√ (2qΔV)/(9.1*10^-31kg) = v
√ (2(1.6*10^-19 C)(10 000V))/ (9.1*10^-31kg) = v
5.92*10^7 = v
-so i calculated the speed of the electron before passes through the plates. i don't know what to do next.. a step-by-step solution would be appreciated, thanks in advance
 
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Suppose that the electric field runs upwards. It's field strength is calculated from E = U/d, where U is the potential difference and d the distance between the plates. The electric force exerted on the electron is F = QE = QU/d. From here on, use what you know about mechanics and movement to find the components of the resultant velocity to find the angle.
 
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