How Is Magnetic Field Strength Calculated in a Solenoid with a Current Balance?

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To calculate the magnetic field strength in a solenoid with a current balance, the relationship between force and magnetic field is essential, specifically using the equations Fm = Fg and BIL = mg. Given the dimensions of the solenoid and the current flowing through it, the magnetic field strength can be derived by rearranging the formula to B = mg / IL. The provided values include a mass of 17.6g, a current of 6.0A, and the lengths of the solenoid sides. The final calculated magnetic field strength is 1.51T. Understanding the induced currents in the magnetic field is crucial for solving this problem effectively.
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Homework Statement



A solenoid lies horizontally with a current balance WXYZ balanced in the solenoid core. Sides WX and ZY are 7.1 cm and side XY is 1.9cm. A current of 6.0A flows through the conductor of the balance. If a 17.6g mass is necessary to balance the current balance what is the magnetic field strength of the solenoid - ANSWER - 1.51T

Homework Equations



Fm=Fg
BIL=mg

The Attempt at a Solution


i attempted to do them seperately.

b= mg/IL that is literally all i can get from this perphaps if i was given a diagram it would help.

Ive tried substituing l as 7,1 and 1.9, adding the two lengths and subtracting them didnt work
anyone know how to do this?
 
Physics news on Phys.org
You should be able to sketch a solenoid and a current balance yourself.
The question is asking you about induced currents due to a magnetic field.
 
You should be able to sketch a solenoid and a current balance yourself.
The question is asking you about induced currents due to a magnetic field.
 

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