Electron and Uniformly Charged Disk

AI Thread Summary
The discussion revolves around calculating the initial acceleration of an electron released from rest on the central axis of a uniformly charged disk. The surface charge density is given as +3.50 µC/m², and the participant is struggling with how the distance from the disk (R, R/100, R/1000) affects the electric field and thus the acceleration. The electric field equation is provided, but the participant is unsure how to apply it for different distances. Additional guidance is suggested, emphasizing the relationship between the radius of the disk and the distance from its center to simplify calculations. The conversation highlights the need for clarity in applying physics equations to find acceleration based on electric forces.
thebert010
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Homework Statement



An electron (e) is to be released from rest on the central axis of a uniformly charged disk of radius R. The surface charge density on the disk is +3.50 µC/m2.
(a) What is the magnitude of the electron's initial acceleration if it is released at a distance R from the center of the disk?
(b) What is the magnitude if it is released at a distance R/100 from the center?
(c) What is the magnitude if it is released at a distance R/1000 from the center?

Homework Equations



<br /> E(z,R)=\frac{\sigma}{2\epsilon_{0}}\left(1-\frac{z}{\sqrt{z^{2}+R^{2}}}\right)<br />



The Attempt at a Solution


So I understand that the acceleration will increase slightly as I get closer to the disk. What I cannot figure out is exactly how R and Fractions of R affect the magnitude of the Electric field. I tried to assume that z=R which allowed me to say that for:
a) I showed that the R term turns into (1-(1/sqrt(2)))
Beyond that, I cannot figure out how to go about b) and c) and my online prof just keeps telling me to look at examples in the book...

Please help!

Thank You!
 
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thebert010 said:

Homework Statement



An electron (e) is to be released from rest on the central axis of a uniformly charged disk of radius R. The surface charge density on the disk is +3.50 µC/m2.
(a) What is the magnitude of the electron's initial acceleration if it is released at a distance R from the center of the disk?
(b) What is the magnitude if it is released at a distance R/100 from the center?
(c) What is the magnitude if it is released at a distance R/1000 from the center?

Homework Equations



<br /> E(z,R)=\frac{\sigma}{2\epsilon_{0}}\left(1-\frac{z}{\sqrt{z^{2}+R^{2}}}\right)<br />



The Attempt at a Solution


So I understand that the acceleration will increase slightly as I get closer to the disk. What I cannot figure out is exactly how R and Fractions of R affect the magnitude of the Electric field. I tried to assume that z=R which allowed me to say that for:
a) I showed that the R term turns into (1-(1/sqrt(2)))
Beyond that, I cannot figure out how to go about b) and c) and my online prof just keeps telling me to look at examples in the book...

Please help!

Thank You!

Well it asks for acceleration. So firstly you know Fe= E*Q What other Force equation helps to find the acceleration of an electron (that has mass) so you can make an equality and find a, acceleration?

Secondly R relates the radius of the disc to how far away the electron is (Z) from the center of the charged disc. So if you made them both = 1 m, would it then be easier to calculate (or "see") the strength of the electric field at a distance Z, that is 1/100 th the radius of disc with a radius of 1 meter? or 100 x closer than the radius of the disc?
 
pgardn,
You are a Godsend

Thank You So Much!
 
thebert010 said:
pgardn,
You are a Godsend

Thank You So Much!

Please inform my wife of this revelation.
 
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