Electron drift speed, Current, and Electric field in hollow wire?

AI Thread Summary
The discussion revolves around calculating the electron drift speed, current density, and electric field in a hollow copper wire carrying a current of 2.50 amps. The relevant equations include I=neeVdA for drift speed, J=I/A for current density, and J=σE for electric field. A participant expresses confidence in their calculations but seeks verification. Another user points out an algebraic error in calculating the wire's area, emphasizing the need to subtract the inner area from the outer area correctly. Accurate calculations are essential for determining the correct values for drift speed, current density, and electric field.
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Homework Statement



A hollow copper wire with an inner diameter of 1.4 mm and an outer diameter of 2.6 mm carries a current of 2.50 amps. Copper has an electron density of 8.5x1028 m-3 and a conductivity of 6.0x107 (ohm m)-1.
a. What is the electron drift speed in the wire?
b. What is the current density in the wire?
c. What is the electric field in the wire?

Homework Equations



a) I=neeVdA
b)J=I/A
c)J=σE

The Attempt at a Solution


I believe I have the correct answers but was just curious if someone could double check me!
Thank you!
 

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Bra, your algebra is wrong. When you find the area, do it for each section separably and subtract them from each other you will see your error. X^2-Y^2 does not equal (X-Y)^2
 
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