Will the electron reach the opposite plate?

physicsstar26
Messages
7
Reaction score
0

Homework Statement



An electron (m= 9.1*10^-31 kg, q=-1.6*10^-19C) moving with a speed of 10^6 m/s enters the region between two parallel and oppositely charged metal plates across which the potential difference is 10V. Will the electron hit the opposite plate- show calculations on how you would solve this.

Homework Equations



Va-Vb= E*dL
q*V= (1/2)mv^2


The Attempt at a Solution



Do you first find the potential then solve for the velocity?
 
Physics news on Phys.org
physicsstar26 said:

Homework Statement



An electron (m= 9.1*10^-31 kg, q=-1.6*10^-19C) moving with a speed of 10^6 m/s enters the region between two parallel and oppositely charged metal plates across which the potential difference is 10V. Will the electron hit the opposite plate- show calculations on how you would solve this.

There seems to be a detail missing in order to decide whether the electron will strike a plate. What is the direction of the electron's initial velocity relative to the plates? How far away from either plate does it enter? This is rather ambiguous as it stands now.
 
There is just a picture with two lines representing the two parallel plates, the first line is labeled 10V and the second line is labeled 0V. There is a small circle in front of the 10V line with an arrow pointing to the right. That is all the information that is provided on the practice test.
 
Do you first find the potential then solve for the velocity?

If the electron enters the region from the positive potential, it will decelerate, since it traveling against the electric field.

One could compare the kinetic energy of the electron against the potential difference of 10V.

If the kinetic energy is less the 10 eV, the electron will not reach the negative plate.

The change in kinetic energy of the electron is related to qV.
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top