Electron wavelength in superconductors

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SUMMARY

The discussion focuses on the electron wavelength in superconductors, specifically distinguishing between the wavelengths of individual electrons and Cooper pairs. Electrons in superconductors have wavelengths that are very short due to their energies being near the Fermi energy, calculated using the formula λ=2π/k, where k is the momentum. In contrast, the wavelength of Cooper pairs is associated with the current density (j) and the density of Cooper pairs (n_s), resulting in a significantly lower wavelength.

PREREQUISITES
  • Understanding of superconductivity principles
  • Familiarity with Fermi energy and Fermi momentum
  • Knowledge of Cooper pairs and their formation
  • Basic grasp of wave-particle duality in quantum mechanics
NEXT STEPS
  • Research the relationship between Cooper pair density and current density in superconductors
  • Study the implications of Fermi energy on electron behavior in superconductors
  • Explore the mathematical derivation of electron wavelength in quantum mechanics
  • Investigate the effects of temperature on superconducting properties and electron wavelengths
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Physicists, materials scientists, and electrical engineers interested in superconductivity and quantum mechanics, particularly those studying electron behavior and Cooper pair dynamics in superconductors.

gildomar
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What is a rough figure for the wavelength of the moving electrons in a superconductor? Or is there no easy answer for that?
 
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You have to distinguish between the wavelength of the Cooper pairs and that of the electrons making up the Cooper pairs. The latter have energies near the Fermi-energy and a momentum near the Fermi-momentum [itex]p_F=\hbar k[/itex] and thus [itex]\lambda=2\pi/k [/ itex] a very short wavelength. <br /> The wavelength of the Cooper pairs is liked to the current j and density n_s of the Cooper pairs as <br /> [itex]j=2e n_s k[/itex] and is very low.[/itex]
 

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