Electrostatic Field Lab Question

AI Thread Summary
To calculate the maximum electric field between two conductors connected to a 6Vdc battery, one can use the relationship between voltage and distance. The electric field can be expressed as volts per meter, leading to the formula E = -ΔV/Δs, where ΔV is the voltage difference and Δs is the distance between the conductors. Although Coulomb's law is typically used for point charges, in this case, the focus is on the voltage difference to determine the electric field strength. The challenge lies in applying these concepts without specific charge values in coulombs. Understanding the relationship between electric field strength and voltage is crucial for solving the problem effectively.
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Homework Statement


Based on Volts and distance, calculate the max Electric Field between lines.

Homework Equations



The Attempt at a Solution


We basically connected a 6Vdc battery to a plate containing two conductors and use a multimeter to plot the lines of flux of the field. To find the max magnitude of the electric field I would apply coulombs law two a point between the two conductors with charges 6 and -6 Volts. However, I don't know how to do that using volts and distance, since I an not given the charges in coulombs. If the electric field can also be defined as Volts/Meter, how would one go about doing that?
 
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Generally we have that ##\mathbf{E}=-\nabla V##, which can also be written as ##\int \mathbf{E} \cdot d{s} = -\Delta V## along some path.

For a small step in the direction of the electric field this means: ##E = -{\Delta V \over \Delta s}##.
 
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