# Electrostatic Force and Coulomb's Law

## Homework Statement

A charge of 6.00 x 10-9C and a charge of -3.00 x 10-9C are seperated by a distance of 60.0 cm. Find the position at which a third charge, of 12.0 x 10-9C, can be placed so that the net electrostatic force on it is zero.

Coulomb's Law

## The Attempt at a Solution

I drew a diagram and I believe that the third charge should be place on the end next to the -3.00 x 10-9C charge. How do I solve for the distance/location of this charge?

vela
Staff Emeritus
Homework Helper
This question belongs in the introductory physics forum.

Let

x = distance from the negative charge to the third charge
d = distance between the positive and negative charges
q1 = positive charge
q2 = negative charge
q3 = third charge.

In terms of the variables:

What's the magnitude of the force on the third charge due to the negative charge?
What's the magnitude of the force on the third charge due to the positive charge?
What's the magnitude of the net force on the third charge?

So you set the magnitude of q1 on q2 equal to the magnitude of q3 on q2 and solve for the distance (d-.6)?

vela
Staff Emeritus
Homework Helper
No. For one thing, d is equal to 0.600 m. It's the distance between the positive and negative charges.

(q1=+6.00 nc) <---------------- d=0.600 m ----------------> (q2=-3.00 nc)

You're trying to find x, the distance between the negative charge and the third charge, which I haven't shown in the diagram. Can you indicate where you think the third charge goes?

(q1=+6.00 nc) <---------------- d=0.600 m ----------------> (q2=-3.00 nc) -------->(q3)

I would get something like that, but I must have fudged my numbers somewhere because I get that it needs to be 3.8m away from q1 and 2.7m away from q2. That wouldn't work as that's more than 0.6m difference, and one needs to keep the problem 1D, else we'll get a net force in the y axis.

vela
Staff Emeritus