Electrostatic Net Force Problem

AI Thread Summary
The discussion focuses on calculating the net electrostatic force on charge q2, which is positioned between charges q1 and q3. Participants clarify that the force on q2 should be calculated separately from q1 and q3 using the formula F=qQ/r^2, where K is given as 9x10^9. After determining the individual forces, the next step is to combine these forces vectorially to find the net force on q2. Suggestions include using graphical methods or trigonometry to sum the forces accurately. The conversation emphasizes the importance of understanding vector addition in solving the problem.
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Homework Statement


I am trying to help a friends daughter understand her physics homework. We have been stumped for hours! We don't really understand what her teacher was talking about and what we have figured out has mostly come from google.

The problem is (this is drawn out no real information is given): q2 1.0c directly north of that is q1 2.0c (the line between them shows a distance of 3m) then directly to the east of q2 is 4.0c and the distance between q2 and q3 is 4m. * (EDIT) Calculate net force on q2.

Homework Equations



F=qQ/r^2
K=9x10^9

The Attempt at a Solution


Lots of google searches. The best we can come up with is that you plug in the information for each individual. (ie q1 q2, q1 q3, q2 q3), but if we did that there is nothing in her notes on how to combine them to come up with a net force? so for q1 q2 would be 3.06*10^9. Are we going about this all wrong? Any help would be appreciated.
 
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Welcome to PF!
The information you gave is clear, except there is no question. What are you trying to calculate? Net force on which charge?
 
Sorry I edited. It says net force on q2.
 
Use the equation you wrote to find the force on q2 due to the charge q1.
Then use it again to find the force due to the 4 C charge.
Finally, add the two force vectors. You can do it by drawing arrows on graph paper, or sketching them on plain paper and finding the sum by trigonometry (law of sines and law of cosines) or by splitting the one at an angle into horizontal and vertical components.
 
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