Electrostatic P.E. vs Gravitational P.E.

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SUMMARY

The discussion focuses on the differences in calculating gravitational potential energy (G.P.E.) and electrostatic potential energy (E.P.E.) for a uniformly distributed mass and a charged metal sphere, respectively. The gravitational potential energy for a planet with mass M and radius R is derived as W = 3GM²/5R. In contrast, the electrostatic potential energy for a charged sphere with charge Q and radius R is incorrectly calculated as W = 3KQ²/5R, highlighting the error in assuming charge distribution. The key distinction is that mass is uniformly distributed in the planet, while charge resides on the surface of the metal sphere.

PREREQUISITES
  • Understanding of gravitational potential energy concepts
  • Familiarity with electrostatics and charge distribution
  • Knowledge of integration techniques in physics
  • Basic principles of spherical symmetry in mass and charge
NEXT STEPS
  • Study the derivation of gravitational potential energy for different mass distributions
  • Learn about electrostatic potential energy calculations for various charge configurations
  • Explore the concept of spherical shells in gravitational and electrostatic contexts
  • Investigate the implications of charge distribution on potential energy in conductors
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and electrostatics, as well as educators looking for clear examples of potential energy calculations.

zorro
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Homework Statement



I am confused b/w two questions:

1) The mass M of a planet Earth is uniformly distributed over a spherical volume of radius R. Find and expression for the energy needed to disassemble the planet against the gravitational pull amongst its constituent particles.

2) A metal sphere of Radius R has a charge Q. Find its potential energy.

The Attempt at a Solution



In both the cases, we have to find the work done in building the whole setup of radius R.

1) The spherical volume may be supposed to be formed by a large number of their concentric spherical shells. Let's consider that there is a core of radius x at any time. The energy needed to disassemble a spherical shell of thickness dx is

dW= Gm1m2/x

On solving and integrating, we get
W = 3GM2/5R

If I proceed analogously for 2), I get W = 3KQ2/5R which is not correct (unlike 1st)
Where is the error?
 
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In the planet the mass is uniformly distributed throughout the volume. For a metallic conductor, all the charge is concentrated on the surface.
 
That was quick!
Yeah you are right...I missed that.
Its much more easier to calculate in the case of E.P.E.

Thanks!
 

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