Electrostatics - Point charge question

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Homework Help Overview

The problem involves calculating the electric field at the position of a negative charge placed at one corner of a square, where three equal positive point charges are located at the other corners. The subject area is electrostatics, specifically focusing on the interactions between point charges and the resulting electric fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the electric field using the formula for electric force and resolves the components for the positive charges. Some participants question the calculations, particularly the distances used for the electric field strength and the relevance of the negative charge.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the correct approach to calculating the electric field, including the need to consider the diagonal distance for one of the charges. There is an exploration of different interpretations of the problem setup and calculations.

Contextual Notes

Participants note potential confusion regarding the distances involved in the calculations and the role of the negative charge in determining the electric field due to the positive charges.

joannananaa
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1. Three equal positive point charges of magnitude Q = 5.00μ C are located at three corners of a square of edge length d = 7.8 cm. A negative charge -15.00μ C is placed on the fourth corner. At the position of the negative charge, what is the magnitude of the electric field due to the three positive charges?



2. Homework Equations :
F=KQ/R^2


3. The Attempt at a Solution :
I have used the equation K=KQ/R^2 to find that the positive points of charge are 7.4E6 N. I wrote these as <7.4E6, 0> and <0, -7.4E6>. I used this equation on the negative charge as well, and got 11.2E6, which I resolved into X and Y components, which were both 7.9E6 and wrote these as <7.9E6, -7.9E6>.

All of this is just following notes from class, and I am unsure of how to actually get the answer.

Any help would be greatly appreciated.
 
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hi joannananaa! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)
joannananaa said:
I have used the equation K=KQ/R^2 to find that the positive points of charge are 7.4E6 N. I wrote these as <7.4E6, 0> and <0, -7.4E6>. I used this equation on the negative charge as well, and got 11.2E6, which I resolved into X and Y components, which were both 7.9E6 and wrote these as <7.9E6, -7.9E6>.

i'm confused :redface:

there are 3 positive charges, 2 at distance d, and 1 at distance d√2 …

how did you get your figures? :confused:
 
Thank you :)

Um...I just plugged them into the formula and wrote one as negative and one as positive. I'm pretty lost.
 
The presence of the negative charge is irrelevant to the magnitude of electric field due to the other 3 positive charges.
Your E field strength of [tex]7.39 \times 10^6[/tex] N/C for the two charges along the square edge was right.
However, for the one along the diagonal, your "r" in [tex]E = k \frac{q}{r^2}[/tex] needs to be the diagonal of the square.
Then you just resolve this into x and y components, and add all 3 electric field strengths as vectors to get the E field strength in the 4th corner.
 

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