Elementary cyclic normal group theory

eileen6a
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Homework Statement


If G is a finite group and let H be a normal subgroup of G with finite index m=[G:H]. Show that a^m\in H for all a\in G.


Homework Equations


order of a group equal the order of element.


The Attempt at a Solution


no idea.
 
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Consider the canonical map \phi : G \rightarrow G/H defined by g \mapsto gH. What can you say about \phi(a^m)?

P.S. "order of a group equal the order of element" is false unless the group is cyclic and the element is a generator of the group.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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