EMF Homework Help: Calculating Resultant Force on a Square with Charges Q and q

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To achieve a net zero force on charge Q located at a vertex of a square with two charges Q at opposite corners and two charges q at the other corners, Q must equal -q. The forces acting on Q include one repulsive force from the other Q and two attractive forces from the q charges. The relationship between these forces can be established by equating the attractive forces from the q charges to the repulsive force from the Q charge. The distance between the charges is also a factor in these calculations, specifically the diagonal distance in the square. The conclusion confirms that Q = -q is indeed correct for achieving equilibrium.
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A charge Q at a vertex of a square and another Q on the opposite corner of the square and other two charges q each of the other vertices. If the force eletrogmanetica on Q is null which the value of Q in terms of q? There is a q such that the resultant force on 4 charges is zero?

My attemp

F = (K.Q.Q)/r^2 + (K.Q.q)/r^2
F = 0
KQ^2 + KQq = 0
Q(KQ + kq) = 0
Q = - q

If q = 0 the resultant force is 0

I correct ?
 
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If the side of the square is r, the length of the diagonal is ...?
At Q three forces are acting. How are they related to get net zero force?
 


rl.bhat said:
If the side of the square is r, the length of the diagonal is ...?
At Q three forces are acting. How are they related to get net zero force?

This is my doubt
 


To get net zero force on Q, Q and q must have opposite sign.
On charge Q, one repulsive force between Q and Q, and two attractive forces between Q and q are acting. What is the distance between Q and Q?
Equate the resultant force of two attractive with the repulsive force to find the relation between Q and q.
 


rl.bhat said:
To get net zero force on Q, Q and q must have opposite sign.
On charge Q, one repulsive force between Q and Q, and two attractive forces between Q and q are acting. What is the distance between Q and Q?
Equate the resultant force of two attractive with the repulsive force to find the relation between Q and q.

Yes I find Q = -q is correct ?
 
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