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In a hydraulic cylinder high amount of load is lifted by applying lower loads in smaller diameter side..

for example, if the diameters of two cylinders is 2cm and 4 cm and i applied a force of 10 N on the 2cm cylinder for 4m downwards. so now the 4cm diameter cylinder could lift a load of 40 N through 1 m... so the work done on both the sides is balanced..

work done = force*displacement

10*4=40*1

But, what if i placed only 20 N load..

the work done on both sides is not balanced....

where does the remaining energy go..?

thanks..

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# Energy balance in hydraulic cylinder

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