For every electron, sure. And if electrons cross the junction, they release this energy.isn't there potential energy through the electric field in the pn junction?
If this potential energy were released into kinetic, then there's no net change in electrons' energy across the diode, and therefore [itex]\Delta[/itex]V is zero not 0.7V. what's wrong?And if electrons cross the junction, they release this energy.
The "energy drop" across a diode refers to the voltage difference between the anode and cathode terminals of the diode when it is forward biased. This voltage drop is typically around 0.7 volts for a silicon diode and 0.3 volts for a germanium diode.
A diode has an energy drop because of the way it is designed. The p-n junction in a diode creates a barrier that allows current to flow in one direction. In order for this current to flow, energy is required to overcome the potential barrier, resulting in the voltage drop.
The energy drop across a diode is an important factor in determining the direction and amount of current flow. When the diode is forward biased, the energy drop allows current to flow easily in one direction. However, when the diode is reverse biased, the energy drop prevents current from flowing in the opposite direction.
The energy drop across a diode is a characteristic of the diode's material and cannot be changed. However, different types of diodes have different energy drops, so selecting the appropriate type of diode for a specific application can help optimize the energy efficiency of a circuit.
Yes, the energy drop across a diode is directly related to its power dissipation. A higher energy drop means that more power is being dissipated in the diode, which can lead to overheating and potential failure. It is important to consider the energy drop when choosing a diode for a particular circuit to ensure it can handle the expected power dissipation.