Energy needed for car to travel-thermodynamics

  • Thread starter Thread starter aal0315
  • Start date Start date
  • Tags Tags
    Car Energy
AI Thread Summary
The discussion revolves around calculating the energy required for a car to travel 150 km, given its fuel efficiency of 25 miles per gallon and the energy yield of gasoline. The conversion of miles per gallon to kilometers per gallon is highlighted, with a conversion factor leading to 40.225 km per gallon. The calculation of gasoline mass is based on the density of gasoline being 68% that of water, resulting in approximately 2.536 kg for the journey. The final energy calculation yields about 1.22 billion joules. The use of Excel for unit conversion is recommended as a helpful tool for simplifying these calculations.
aal0315
Messages
41
Reaction score
0

Homework Statement


Gasoline yields 4.8x10^7 J/kg when burned. How much energy does a car use traveling a distance of 150 km if it gets 25 miles per (British) gallon? Assume that the density of gasoline is 68% that of water.


Homework Equations





The Attempt at a Solution


I don't really know where to begin with this question. All i know is that 25mpg is equal to 40.225km per gallon.
Any suggestions?
 
Physics news on Phys.org
The crux of this question really is in unit conversion. It assumes that you know that a litre of water has a mass of 1 kg so that you can work out the mass of 25 gallons of gasoline.

Does this help?
 
So i do 40.225 x 68% = 27.35 kg to get the mass of 25 gallons of gasoline?

and what next? I don't know a formula to figure out the energy given the information.
 
ok does this look right to anyone:
25gallons x 1.609 = 40.225km per gallon

150km/40.225 = 3.729 gallons to travel 150km

3.729 x 68% = 2.536kg

2.536 x 4.8x10^7J/kg = 1.22x10^9J ?
 
One of the most helpful tools I have found is the Unit Conversion in Excel (http://www.unitconversionaddin.com ). This simply works because students (like me) are able to do the unit conversion automatically in excel like a program. I don't have to either search on the internet for the conversion value or have to write out some excel function. The download is like 5 bucks and has saved me hours of stress and time.
 
Last edited by a moderator:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top