Energy to separate charge +e and -e

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The discussion focuses on deriving the energy required to separate an electric charge +e and a charge -e from an initial separation distance d to infinity. The user applied Coulomb's law and integrated the force equation to find the work done. The resulting expression for the work is W = e² / (4π * ε₀ * d). The user expresses confidence in the correctness of this solution, relating it to the concept of electric potential. The conversation emphasizes the integration process and the relationship between work and potential energy in electrostatics.
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Homework Statement


Derive an expression for the energy required to separate to infinity an electric charge +e and a charge -e, their initial separation being d.

Homework Equations



F = (q1*q2)/(4∏ * ε0 * d2)

The Attempt at a Solution


Basically what I've done is first make q1= +e and q2= -e and substituted them into the equation above. I then integrated this equation as show below...

Work done = d F = d -e2 / (4∏ * ε0 * d2)

After integrating this with respect to d, I get the answer...

W = e2 / (4∏ * ε0 * d)

Is this correct or did i make it all up in my head, thanks for any replies :)
 
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I think this is correct. The potential of a charge, v = kq/r , is found this way, i.e. by integrating from d to infinity of a test charge and then dividing by the charge.
 
An easier way to do this is to work out the change in potential energy.
W = ΔU
 
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