Engery Conservation in Oscillatory Motion

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Homework Help Overview

The discussion revolves around energy conservation in oscillatory motion, specifically involving a block sliding on a frictionless surface and its interaction with a spring. The problem includes calculating the compression of the spring and the time the block is in contact with it before coming to rest.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy principles to determine the spring compression and the time of contact. They express confusion regarding the relationship between the period of oscillation and the time the block is in contact with the spring, questioning why it is a quarter of the period instead of half.

Discussion Status

Participants are engaging in clarifying the original poster's understanding of the relationship between displacement and time in simple harmonic motion. Some guidance has been offered regarding the nature of oscillatory motion, and there is an acknowledgment of the need for visual aids to enhance comprehension.

Contextual Notes

The original poster is grappling with the interpretation of the time spent in contact with the spring, specifically in relation to the period of oscillation, and has referenced external resources for further clarification.

Julio Cesar
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A 0.980kg block slides on a frictionless, horizontal surface with a speed of 1.32m/s. The block encounters an unstretched spring with a force constant of 245N/m.

(a)How far is the spring compressed before the block comes to rest?

(b) How long is the block in contact with the spring before it comes to rest?




Equations: Conservation of energy using a spring.

Ei=Ef

1/2mvo2 = 1/2kA2

A= vo√m/k

Question (b): T = 2∏√m/k




3. Attempt at solution shows:

A= 0.0835m

T= 0.397s

As far as the calculations, I know the amplitude as well as the period of one complete occilation. However, when the question asks me how long is the block in contact with the spring before it comes to rest...

Well, my senses tell me that it would be half a period since the spring is compressed when the block comes in contact with it and stops. (v= 0m/s)

The answer it gives me is 0.0993s...?!

Where does this come from; that's not half a period that's a quarter of a period. The answer may be staring at be straight in the face but I just don't get it. Can someone explain why the answer is 1/4 the period instead of 1/2 the period?

Thanks.

 
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Wow! I feel like an idiot now. I've just spent the last hour just looking at the diagram, wondering why and didn't even think to draw out a sine function, lol!

Thanks so much, this helps out a ton!
 
A drawing always helps.

ehild
 

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