- #1
Quipzley
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Find a) the energy absorbed as heat and b) the change in entropy of a 2 kg block of copper whose temperature is increased reversibly from 25 degrees C to 100 degrees C. The specefic heat of copper is 386 J/kg * K.
a) Q = 386 J/kg *K * (373 K - 298 K) * 2 kg = 57900 J
b) the change in entropy = integral(dQ / T). I'm unsure of how to integrate to be able to have a usable formula?
a) Q = 386 J/kg *K * (373 K - 298 K) * 2 kg = 57900 J
b) the change in entropy = integral(dQ / T). I'm unsure of how to integrate to be able to have a usable formula?