Find a) the energy absorbed as heat and b) the change in entropy of a 2 kg block of copper whose temperature is increased reversibly from 25 degrees C to 100 degrees C. The specefic heat of copper is 386 J/kg * K.(adsbygoogle = window.adsbygoogle || []).push({});

a) Q = 386 J/kg *K * (373 K - 298 K) * 2 kg = 57900 J

b) the change in entropy = integral(dQ / T). I'm unsure of how to integrate to be able to have a usable formula???

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# Homework Help: Entropy integration problem

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