Engineering Eq. Logic Expression for Circuit 2

[DeathDealer]

Homework Statement

https://www.dropbox.com/s/d3qdr96n27j8wa7/circuit.png?dl=0

The questions is as follows: For each circuit write the equivalent logic expression.

Homework Equations

(B' + C) * A (?) My Attempt at circuit 2
(A* (A' * C') * B') + (A * C * B) My Attempt at Circuit 1

The Attempt at a Solution

[/B]
I attempted circuit 2 and circuit 1 but circuit 2 is easier because i think i know some of the basics but circuit 1 was very complicated (I did look at it and try to work it out, my best guess really) and i really need an assist on that as for circuit 2 here is what I got and my reasoning: (B' + C) * A

In the second circuit you have three gates. A "NOT" gate, a "OR" gate and an "AND" gate.

1) "NOT" gates inverts the input. An input of '1' for a NOT gate would result in a '0' and an input of '0' would result in a '1'. So if the input is say x we denote the output by x′ where x′ denote the opposite of x. So B becomes B'.

2) "OR" gates take two inputs and add then together. Basically this means if the two inputs are x and y the output will be x+y. So B' becomes B'+C

3) "AND" gates take two inputs and multiplies then together. Hence if the two inputs are x and y the output will be xy. So B' + C becomes (B'+C) * A

 

[axmls]

Yes, that is correct. Have you made an attempt for circuit 1?

 

[DeathDealer]

Yes, that is correct. Have you made an attempt for circuit 1?

I found it very hard. I know what the gates mean but all those pathways going everywhere is just to confusing. BUT if i had to guess I would say something like: (A* (A' * C') * B') + (A * C * B).

 

[axmls]

Just start from the right side, and work backwards slowly. Take your time.

 

[DeathDealer]

Just start from the right side, and work backwards slowly. Take your time.

Am I close? (A* (A' * C ') * B ') + (A * C * B)

 

[DeathDealer]

I also came up with some tables is this right?

 

[DeathDealer]

I think i mucked up circuit 1: its (A* (A' * C ')' * B ') + (A * C * B). Could someone tell me if I'm right?

 

[axmls]

I think i mucked up circuit 1: its (A* (A' * C ')' * B ') + (A * C * B). Could someone tell me if I'm right?

Yes, that looks correct.