Equation of a Surface relative to a basis

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Discussion Overview

The discussion revolves around transforming the equation of a surface from the standard basis to a new coordinate system defined by specific basis vectors. Participants explore the mathematical process of finding the transition matrix and expressing the surface equation in terms of the new coordinates.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the equation of a surface in standard coordinates and seeks to express it in terms of a new basis defined by vectors F1, F2, and F3.
  • Another participant discusses the transition matrix from the standard basis to the new basis and questions how it transforms specific vectors.
  • A later reply elaborates on the relationship between the standard basis and the new basis, suggesting a method to express the standard basis vectors as linear combinations of the new basis vectors.
  • One participant affirms the correctness of the transition matrix and proposes substituting the transformed coordinates into the surface equation.

Areas of Agreement / Disagreement

Participants generally agree on the need to find the transition matrix and express the surface equation in the new basis, but there is some uncertainty regarding the specific transformations and representations involved.

Contextual Notes

There are unresolved aspects regarding the correctness of the transition matrix and the specific transformations of the basis vectors, as well as the implications of these transformations for the surface equation.

shonen
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Equation of a Surface relative to the standard basis is

X1^1 + 2X2^2 + 3x^3 -4x1x2 -4x2x3 =0

Now the question ask to find the equation of above surface relative to the cordinate system with basis vectors

F1= (2/3,2/3,1/3)
F2= (1/3,-2/3,2/3)
F3= (2/3,-1/3,-2/3)

Now i found the transition matrix from the standard basis ( (1,0,0),(0,0,1),(0,0,1) ) to (F1,F2,F3) which was found to be

(2/3, 2/3, 1/3)
(1/3,-2/3, 2/3)
(2/3 -1/3,-2/3)

and got an arbitrary vector (a,b,c) in coordinate system in terms of coordinate (x1,x2,x3) relative to the standard basis

27a = 2x1 + 2x2 +x3
27b = x1 -2x2 +2x3
27bc= 2x1 -x2 -2x3

Problem is expressing the above equation of a surface in terms of a,b,and c.
 
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shonen said:
Now i found the transition matrix from the standard basis ( (1,0,0),(0,0,1),(0,0,1) ) to (F1,F2,F3) which was found to be

(2,2,1)
(1-2 3) * (1/(3)^3)
(2-1-2)

How will that matrix transform (0,0,1) to the correct representation in terms of F1,F2,F3?
 
Stephen Tashi said:
How will that matrix transform (0,0,1) to the correct representation in terms of F1,F2,F3?
Let B be the matrix whose row are the standard basis, and C the matrix whose row i is the 3x1 basis vector Fi (i=1,2,3) for the coordinate system. and

p =(2/3, 2/3, 1/3)
(1/3,-2/3, 2/3)
(2/3 -1/3,-2/3)

Then

B=PT (P transpose)(C) ---(2)

Where P the transition matrix from the standard basis to C. Is it ok now ?

In the above equation I've just expressed the standard basis as a linear combination of F1,F2,F3. From definition the transition matrix from standard basis to F1,F2,F3 is one whose columns are the coordinates of the standard basis relative to F1,F2,F3.
 
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I think that version of [tex]P[/tex] is correct.

[tex]X_1 = 1 X_1 + 0 X_2 + 0 X_3 = \begin{pmatrix} 1\\0 \\0 \end{pmatrix}[/tex] in the standard basis. Use [tex]P^T[/tex] to transform [tex]X_1[/tex] into the [tex]F[/tex] basis. You get some vector [tex]\begin{pmatrix} a \\b \\c \end{pmatrix}[/tex] so [tex]X_1 = a F_1 + b F_2 + c F_3[/tex] and you can substitute that for [tex]X_1[/tex] in the equation for the surface. etc.
 

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