Equation of sphere given 3 pointcalc 3

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Homework Statement


Find the equation of a sphere that contains the points (-3,0,0) (3,4,4) and (-4,3,4) if its center lies on the xz plane


Homework Equations


Not sure...i used the distance formula though


The Attempt at a Solution


This class has just started and i have no idea where to start with this becuase this is our first homework! I am trying to find a point equidistant from all three points that could be the center, but I could only find a plane which I found to be 2z+3x=4


Please help! I am really frustrated =(
 
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memish said:

Homework Equations


Not sure...i used the distance formula though

General of a sphere

(x-h)2+(y-j)2+(z-k)2=r2 where (h,j,k) is the centre of the sphere.

you have three points and what plane the centre lies on
 
This question is like an analogy to those involving simultaneous equations. ;) Try to substitute the 3 points into the general equations and solve for the unknowns.
 
thanks, rockfreak

lkh - what do you mean by the problems with simultaneous equations?
 
ohhh ok thanks! i got it it was much simpler than i thought :)
 
Because the center lies on the xz plane than its coordinates are (x,0,z)

The equation would be:

(x-x_0)^2+y^2+(z-z_0)^2=r^2
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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