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Equilibrium - Calculating Kp

  1. Mar 5, 2009 #1
    1. The problem statement, all variables and given/known data

    Given a sealed vessel at 2000K, initially contains I2 (g) + Cl2 (g) <- -> 2 ICl (g) with partial pressures .3 atm, .3 atm and .5 atm respectively. At equilibrium the partial pressure of ICl has increased by 52.8% (so .764 atm)... calculate Kp. But that is one part that confuses me. Does only one pressure change?

    Anyway.. I just did a Kp calculation for a previous question with no change and got the proper answer (it's given)... but using an ICE table in that question allowed me to solve for x to figure out the diffferent pressures... I tried to do that here but Got:

    I2 Cl2 ICl
    (.3-x) (.3-x) (.5+2x)

    but if I add them together and equal to the total pressure (1.1 atm) ... everything cancels out. I admit I don't have a great understanding of pressures yet... any help would be greatly appreciated.
  2. jcsd
  3. Mar 5, 2009 #2


    User Avatar

    Staff: Mentor

    All partial pressures change in this case.
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