Equilibrium constant and rate constant

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SUMMARY

The discussion clarifies the relationship between the equilibrium constant (K) and the rate constant (k) in chemical kinetics. K represents the ratio of equilibrium concentrations, while k denotes the rate constant for a specific reaction. It is established that the equilibrium constant can be expressed as the ratio of the forward and reverse rate constants. This distinction is crucial for understanding reaction dynamics and equilibrium behavior in chemical systems.

PREREQUISITES
  • Understanding of chemical kinetics
  • Familiarity with equilibrium concepts
  • Knowledge of rate laws and reaction rates
  • Basic grasp of chemical thermodynamics
NEXT STEPS
  • Study the derivation of the equilibrium constant from rate constants
  • Learn about the Arrhenius equation and its application to rate constants
  • Explore the differences between Kp and Kc in gas-phase reactions
  • Investigate the impact of temperature on equilibrium constants
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Chemistry students, chemical engineers, and researchers in the field of physical chemistry who are looking to deepen their understanding of reaction kinetics and equilibrium relationships.

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Hi every body,

I am just asking myself if the two constants K and k have some relations with each other. Could anyone explain more about this?

Thanks
 
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could you be more specific? Are you talking about Ka, Kb, Kp, Kc or something else?
 
Ha, I failed to notice one is capitalized (K) and the other is not(k)! (im going blind)

I should then say that the relations seem more than obvious.
 
Thank you for your answering me. Anyway, could you please explain a little bit more ?
 
k is a rate constant for kinetics

K is a ratio of equillibrium compositions

I think that is what you needed?
 
sicjeff said:
k is a rate constant for kinetics

K is a ratio of equillibrium compositions

I think that is what you needed?

No, they are different, totally.
 
Equilibrium is where the forward reaction and reverse reaction have the same rate.

The equilibrium constant will be equal to the ratio of the rate constants.

Is that what you were looking for?
 

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