Equivalent capacitance in complex circuit

[quietriot1006]

Homework Statement

Hello, I was given this problem as a homework assigment.
Each capacitor in the figure has capacitance C. What is the equivalent capacitance between points a and b?
The answer is given in "C_eq/C"

Homework Equations

I used the "C_eq={(1/C_1)+(1/C_2)+...(1/C_n)}^-1" for the capacitors in series.
I used the "C_eq=(C_1)+(C_2)+...(C_n) for the capacitors in parallel.

The Attempt at a Solution

Combining everything that was in parallel and everything that was in series until it come down to one capacitor, the answer that i get is C or 1. Any ideas on what I am doing wrong or if I am inputing the answer in the wrong way?

 

[Redbelly98]

Welcome to PF.

It may be just me, but I don't see any series capacitors in this circuit.

This one may require Kirchoff's loop and node laws (also known as KVL and KCL).

 

[tanerr]

I think it is 2C.
If you consider capacitors like resistances, you will see bridge and one of the capacitor behaves as open circuited.