Equivalent capacitance in complex circuit

  • #1

Homework Statement



Hello, I was given this problem as a homework assigment.
Each capacitor in the figure has capacitance C. What is the equivalent capacitance between points a and b?
The answer is given in "C_eq/C"

30.CP86.jpg


Homework Equations



I used the "C_eq={(1/C_1)+(1/C_2)+.....(1/C_n)}^-1" for the capacitors in series.
I used the "C_eq=(C_1)+(C_2)+.....(C_n) for the capacitors in parallel.

The Attempt at a Solution



Combining everything that was in parallel and everything that was in series until it come down to one capacitor, the answer that i get is C or 1. Any ideas on what I am doing wrong or if im inputing the answer in the wrong way?
 

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Answers and Replies

  • #2
Redbelly98
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Welcome to PF.

It may be just me, but I don't see any series capacitors in this circuit.

This one may require Kirchoff's loop and node laws (also known as KVL and KCL).
 
  • #3
2
0
I think it is 2C.
If you consider capacitors like resistances, you will see bridge and one of the capacitor behaves as open circuited.
 

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