Engineering Equivalent Single Load for Complex Delta and Y Connected Loads

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The discussion revolves around finding the equivalent single delta-connected load for complex delta and Y-connected loads. The initial uncertainty involves whether to calculate the resistances of both configurations and combine them in parallel or directly find the delta load's impedance. It is suggested to transform the Y load to a delta and then sum the two parallel delta loads into a single delta load. Additionally, transforming the resulting delta back to a Y load is necessary for further analysis. Ultimately, the approach to load summation can be taken from either the delta or Y side, leading to consistent results.
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Homework Statement


a) the equivalent single Δ-connected load
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The Attempt at a Solution


I am not sure if the question is asking me to find the resistance of both delta and y connected loads then work out them both in parallel. After I have the answer find a delta load for a circuit that equals this or simply find the delta loads impedance. That seems a bit easy from what i have done on my last question.
The questions after the question number a make me think i should do it the first way i said but i am a bit unsure.
also question b says i need to transform delta to y in question a but i don't see why.
Any advice please
 

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Note that the loads are complex.
Approach load summation from the Δ side.
3a. Transform the Y load to a Δ, then sum the two parallel Δs into a single Δ load.
3b. Transform that parallel sum Δ from 3a, into a single Y load.
Now approach load summation from the Y side.
3c. Transform the Δ load of fig 3, to a Y, then sum it in parallel with the existing Y load to make one Y load.
3d. Find the real power dissipated in the complex Δ load.
billyray said:
also question b says i need to transform delta to y in question a but i don't see why.
So you can see that it does not matter how you approach the result. The Yb solution should be the same as the Yc solution.
 
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