Error Analysis: Check doop=1.021+-1.3e-3

AI Thread Summary
The discussion revolves around calculating the value of "doop" using the formula doop=a^3/(a^3-(b^2*d*s0/L) with given values for a, b, s0, and d. Participants are trying to verify the calculated result of doop=1.021±1.3e-3. There is confusion regarding the variable L, which is specified as L=208.3±1 cm, and whether all variables are in consistent units. Clarification is sought on the formula's structure, particularly the correct interpretation of the denominator. The conversation highlights the importance of unit consistency and formula accuracy in error analysis.
zak8000
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Homework Statement


doop=a^{3}/(a^{3}-(b^{2}*d*s0/L)

a=4.65+-0.03
b=4.60+-0.03
s0=3.987+-6.906e-3
d=5.05+-3.03

could someone please check that if they get the same answer as me:
doop=1.021+-1.3e-3

Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution

 
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You haven't specified L.
 
ops L=208.3+-1cm
 
Do the other values have units associated with them?
 
yep all cm's
 
I see. Then perhaps your rendering of the formula is confusing me, since it looks like the parameter b has an exponent that would have units in it.

Is the denominator a3 - b2*d*S0/L or is it a3 - b2*d*S0/L ?
 

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