Error Calculation: 1/a with Error

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To calculate 1/a with error for a = 0.00083 ± 0.00002m, the appropriate method involves using the error propagation rules for division. The formula for error propagation in division states that the relative error in the result is the square root of the sum of the squares of the relative errors of the variables involved. Specifically, for Z = 1/a, the error can be calculated using ΔZ = Z√[(Δa/a)²]. Concerns were raised about the resulting error being excessively large, prompting a request for clarification on the calculations. Properly applying these rules should yield a manageable error estimate.
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Homework Statement



a = 0.00083 ± 0.00002m

what is 1/a with error

Homework Equations



rules for combining errors

z = xy or z=x/y σ(z) = [σ(x)]2[σ(y)]2

The Attempt at a Solution



I tried doing 1/a ± 1/error

but the error gets too big... is there a rule for this kind of situation?
 
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jmher0403 said:

Homework Statement



a = 0.00083 ± 0.00002m

what is 1/a with error


Homework Equations



rules for combining errors

z = xy or z=x/y σ(z) = [σ(x)]2[σ(y)]2


The Attempt at a Solution



I tried doing 1/a ± 1/error

but the error gets too big... is there a rule for this kind of situation?

The rule for Z = X*Y or Z = X/Y is
$$\Delta Z = Z\sqrt{\left(\frac{\Delta X}{X}\right)^2 + \left(\frac{\Delta Y}{Y}\right)^2}$$
A rule for powers of a value:

If ##Z = X^n## then
$$\Delta Z = n x^{(n - 1)} \Delta X$$
In your case n = -1.

Can you present your calculations showing that your error result is too large? (and too large as compared to what?)
 
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