Evaluating Integral: $\int_0^{\pi/2} \frac{1}{y+\cos x}dx$

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How do you evaluate an integral such as:
\begin{equation}
\int_0^\frac{\pi}{2} \frac{1}{y+cosx} \, dx
\end{equation}
I was thinking whether to treat y as a constant and then integrate as such and be left with an arbitrary constant that is a function of y. This constant, f(y), should then disappear when evaluating the definite integral...?
 
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That depends on what you want to find out. Does y have some fixed relationship to x?
Usually, y will be a constant, and the definite integral will still depend on y in the same way the integral will give different results if you replace y by different real numbers.
 
I’ve attached my attempt at the question. Just wanted to know what you think? I’ve got a definite integral that is a function of y, I(y), and have used the substitution t=tan(x/2).
 

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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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