Evaluating Integral with a natural log

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Homework Statement


\int9s9^s ds

Homework Equations


∫udv=uv-∫9^sds-∫vdu

The Attempt at a Solution


u=9s
du=9ds

dv=9^s ds
v=∫9^sds
=∫3^(2s) ds
=3^(2s)/[2ln(3)]
this is as far as i have gotten. Am i correct so far?
 
Last edited:
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Yes, that is correct. You didn't really need to reduce to 3, that is exactly the same as
\int 9^s ds= 9^s/ln(9)
 

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