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Could someone please help me evaluate the integral with mathematica
[itex]\int \frac{dx}{(a(1+x^{-1})+b(1+x^{2})-1)^{1/2}}[/itex]
For better in your code the integral must be:
1/sqrt[a(1+(1/x))+b(1+x^(2))-1]
For [itex]a≤1[/itex] and for cases:
A)[itex]0<b<1[/itex]
B)[itex]b>1[/itex]
I am sorry,but I haven't been able to receive mathematica yet... *sad face*
Deep thanks in regard
*not to be misunderstood that I'm asking to find everything ready I even know the codes I'd use in such a case:
Expand[Assuming[0<a<1 && b>1, Integrate[1/sqrt[a(1+(1/x))+b(1+x^(2))-1]]]]
Expand[Assuming[0<a<1 && 0<b<1, Integrate[1/sqrt[a(1+(1/x))+b(1+x^(2))-1]]]]
(if there would be an error I'd try to remove the expand)...I just still don't have the software at hand
[itex]\int \frac{dx}{(a(1+x^{-1})+b(1+x^{2})-1)^{1/2}}[/itex]
For better in your code the integral must be:
1/sqrt[a(1+(1/x))+b(1+x^(2))-1]
For [itex]a≤1[/itex] and for cases:
A)[itex]0<b<1[/itex]
B)[itex]b>1[/itex]
I am sorry,but I haven't been able to receive mathematica yet... *sad face*
Deep thanks in regard
*not to be misunderstood that I'm asking to find everything ready I even know the codes I'd use in such a case:
Expand[Assuming[0<a<1 && b>1, Integrate[1/sqrt[a(1+(1/x))+b(1+x^(2))-1]]]]
Expand[Assuming[0<a<1 && 0<b<1, Integrate[1/sqrt[a(1+(1/x))+b(1+x^(2))-1]]]]
(if there would be an error I'd try to remove the expand)...I just still don't have the software at hand
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